Drifters+R

Bush Bush Grass Grass Wood Wood

1 Black Green Orange Red Yellow

10 2 2 5 1 2 Black Green Orange Red

6 6 4 4 3 Black Green Orange Red Yellow

5 5 2 5 3 4 Black Green Red Yellow

4 5 9 2 5 Black Green Orange

7 10 3 6 Black Green

10 10

As some of the results are less than 3; we will combine results of Yellow snails with Green snails and Orange with Red snails. Expected = 14 Chi-sq = 0.286 || 9 Expected = 44/3 Chi-sq = 2.189 || 15 Expected = 11 1/3 Chi-sq = 1.186 || 40 || Expected = 14 Chi-sq = 1.786 || 15 Expected = 44/3 Chi-sq = 0.007576 || 16 Expected = 11 1/3 Chi-sq = 98/51 || 40 || Expected = 14 Chi-sq = 9/14 || 20 Expected = 44/3 Chi-sq = 64/33 || 3 Expected = 11 1/3 Chi-sq = 625/102 || 40 || X^2 = 16.086 (3 d.p.) Degree of Freedom = 4 P-value = 0.00290591
 * Analysis**
 * || B || G + Y || O + R || Total ||
 * Population 1 (Bush) || 16
 * Population 2 (Grass) || 9
 * Population 3 (Wood) || 17
 * || 42 || 44 || 33 || 120 ||

Therefore, there is a 0.00290591 chance that we would get the results if the null hypothesis is true.

Critical value (2-tailed) = 9.49 Our results are significant as the Chi-square value is greater than the critical value.